Leetcode

Container With Most Water

  • Time:O(1)
  • Space:O(1)

C++

class Solution {
 public:
  int maxArea(vector<int>& height) {
    int ans = 0;
    int l = 0;
    int r = height.size() - 1;

    while (l < r) {
      const int minHeight = min(height[l], height[r]);
      ans = max(ans, minHeight * (r - l));
      if (height[l] < height[r])
        ++l;
      else
        --r;
    }

    return ans;
  }
};

JAVA

class Solution {
  public int maxArea(int[] height) {
    int ans = 0;
    int l = 0;
    int r = height.length - 1;

    while (l < r) {
      final int minHeight = Math.min(height[l], height[r]);
      ans = Math.max(ans, minHeight * (r - l));
      if (height[l] < height[r])
        ++l;
      else
        --r;
    }

    return ans;
  }
}

Python

class Solution:
  def maxArea(self, height: List[int]) -> int:
    ans = 0
    l = 0
    r = len(height) - 1

    while l < r:
      minHeight = min(height[l], height[r])
      ans = max(ans, minHeight * (r - l))
      if height[l] < height[r]:
        l += 1
      else:
        r -= 1

    return ans