Leetcode

Divide Chocolate

  • Time:O(n\log(\Sigma |\texttt{sweetness[i]}|))
  • Space:O(1)

C++

class Solution {
 public:
  int maximizeSweetness(vector<int>& sweetness, int k) {
    int l = sweetness.size() / (k + 1);
    int r = accumulate(begin(sweetness), end(sweetness), 0) / (k + 1);

    while (l < r) {
      const int m = (l + r) / 2;
      if (canEat(sweetness, k, m))
        l = m + 1;
      else
        r = m;
    }

    return canEat(sweetness, k, l) ? l : l - 1;
  }

  // true if can eat m sweetness (min sweetness of each piece)
 private:
  bool canEat(const vector<int>& sweetness, int k, int m) {
    int pieces = 0;
    int sum = 0;  // running sum

    for (const int s : sweetness) {
      sum += s;
      if (sum >= m) {
        if (++pieces > k)
          return true;
        sum = 0;
      }
    }

    return false;
  };
};

JAVA

class Solution {
  public int maximizeSweetness(int[] sweetness, int k) {
    int l = sweetness.length / (k + 1);
    int r = Arrays.stream(sweetness).sum() / (k + 1);

    while (l < r) {
      final int m = (l + r) / 2;
      if (canEat(sweetness, k, m))
        l = m + 1;
      else
        r = m;
    }

    return canEat(sweetness, k, l) ? l : l - 1;
  }

  // true if you can eat m sweetness (min sweetness of each piece)
  private boolean canEat(int[] sweetness, int k, int m) {
    int pieces = 0;
    int sum = 0; // running sum

    for (final int s : sweetness) {
      sum += s;
      if (sum >= m) {
        if (++pieces > k)
          return true;
        sum = 0;
      }
    }

    return false;
  }
}

Python

class Solution:
  def maximizeSweetness(self, sweetness: List[int], k: int) -> int:
    l = len(sweetness) // (k + 1)
    r = sum(sweetness) // (k + 1)

    # True if you can eat m sweetness (min sweetness of each piece)
    def canEat(m: int) -> bool:
      pieces = 0
      sum = 0  # running sum

      for s in sweetness:
        sum += s
        if sum >= m:
          pieces += 1
          if pieces > k:
            return True
          sum = 0

      return False

    while l < r:
      m = (l + r) // 2
      if canEat(m):
        l = m + 1
      else:
        r = m

    return l if canEat(l) else l - 1