Leetcode

Implement strStr()

  • Time:O((m - n)n), where m = |\texttt{haystack}| and n = |\texttt{needle}|
  • Space:O(1)

C++

class Solution {
 public:
  int strStr(string haystack, string needle) {
    const int m = haystack.length();
    const int n = needle.length();

    for (int i = 0; i < m - n + 1; i++)
      if (haystack.substr(i, n) == needle)
        return i;

    return -1;
  }
};

JAVA

class Solution {
  public int strStr(String haystack, String needle) {
    final int m = haystack.length();
    final int n = needle.length();

    for (int i = 0; i < m - n + 1; ++i)
      if (haystack.substring(i, i + n).equals(needle))
        return i;

    return -1;
  }
}

Python

class Solution:
  def strStr(self, haystack: str, needle: str) -> int:
    m = len(haystack)
    n = len(needle)

    for i in range(m - n + 1):
      if haystack[i:i + n] == needle:
        return i

    return -1