Leetcode

Linked List Cycle

  • Time:O(n)
  • Space:O(1)

C++

class Solution {
 public:
  bool hasCycle(ListNode* head) {
    ListNode* slow = head;
    ListNode* fast = head;

    while (fast && fast->next) {
      slow = slow->next;
      fast = fast->next->next;
      if (slow == fast)
        return true;
    }

    return false;
  }
};

JAVA

public class Solution {
  public boolean hasCycle(ListNode head) {
    ListNode slow = head;
    ListNode fast = head;

    while (fast != null && fast.next != null) {
      slow = slow.next;
      fast = fast.next.next;
      if (slow == fast)
        return true;
    }

    return false;
  }
}

Python

class Solution:
  def hasCycle(self, head: ListNode) -> bool:
    slow = head
    fast = head

    while fast and fast.next:
      slow = slow.next
      fast = fast.next.next
      if slow == fast:
        return True

    return False