Leetcode

Logical OR of Two Binary Grids Represented as Quad-Trees

May 26, 2022 by aAshish

  • Time:O(n^2 \log_4 n)
  • Space:O(\log_4 n)

C++

 
class Solution {
 public:
  Node* intersect(Node* quadTree1, Node* quadTree2) {
    if (quadTree1->isLeaf)
      return quadTree1->val ? quadTree1 : quadTree2;
    if (quadTree2->isLeaf)
      return quadTree2->val ? quadTree2 : quadTree1;

    Node* topLeft = intersect(quadTree1->topLeft, quadTree2->topLeft);
    Node* topRight = intersect(quadTree1->topRight, quadTree2->topRight);
    Node* bottomLeft = intersect(quadTree1->bottomLeft, quadTree2->bottomLeft);
    Node* bottomRight = intersect(quadTree1->bottomRight, quadTree2->bottomRight);

    if (topLeft->val == topRight->val &&
        topLeft->val == bottomLeft->val &&
        topLeft->val == bottomRight->val &&
        topLeft->isLeaf && topRight->isLeaf &&
        bottomLeft->isLeaf && bottomRight->isLeaf)
      return new Node(topLeft->val, true);
    return new Node(false, false, topLeft, topRight, bottomLeft, bottomRight);
  }
};

JAVA

 
class Solution {
  public Node intersect(Node quadTree1, Node quadTree2) {
    if (quadTree1.isLeaf)
      return quadTree1.val ? quadTree1 : quadTree2;
    if (quadTree2.isLeaf)
      return quadTree2.val ? quadTree2 : quadTree1;

    Node topLeft = intersect(quadTree1.topLeft, quadTree2.topLeft);
    Node topRight = intersect(quadTree1.topRight, quadTree2.topRight);
    Node bottomLeft = intersect(quadTree1.bottomLeft, quadTree2.bottomLeft);
    Node bottomRight = intersect(quadTree1.bottomRight, quadTree2.bottomRight);

    if (topLeft.val == topRight.val &&
        topLeft.val == bottomLeft.val &&
        topLeft.val == bottomRight.val &&
        topLeft.isLeaf && topRight.isLeaf &&
        bottomLeft.isLeaf && bottomRight.isLeaf)
      return new Node(topLeft.val, true);
    return new Node(false, false, topLeft, topRight, bottomLeft, bottomRight);
  }
}